Question

proved that.
sec 840.cot(-945)+sin600.tan(-690)=3/2
100 point​

Answer 1

(-1/2) + 2 = -3/2 = RHS

Given : Sin 600° * Tan (-690°) + Sec 840° * Cot(-945°) = Sin 600° x -Tan 690° + Sec 840° x -Cot 945° = Sin ( 720° - 120°) x - Tan ( 720° - 30°) + Sec ( 720° + 120°) x -Cot (1080° - 135°) = - Sin 120° x -(- Tan 30°) + Sec 120° x - (-Cot 135°) =- Sin (180° - 60°) x Tan 30° + Sec (180° - 60°) x Cot (180°- 45°) = (-Sin 60°x Cot 60°) - (sec 60° x -Cot 45°) = (- √3 / 2 x 1 / √3 )- ( 2 x - 1) = - 1 / 2 + 2 = 3 / 2.

Answer 2

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