proved that sin²17π/18 = Sin²π/18
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3
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Answered by
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ANSWER
k=sinπ/8sin5π/18sin5π/18sin7π/18
=sin10
∘
sin
50
∘
sin
70
∘
=
2
1
[cos40
∘
−cos60
∘
]sin70
∘
=
2
1
cos40
∘
sin70
∘
−
4
1
sin70
∘
=
4
1
[sin110
∘
+sin30
∘
]−
4
1
sin70
∘
=
4
1
sin(180
∘
−70
∘
)+
4
1
×
2
1
−
4
1
sin70
∘
=
8
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