Question

provethat 4+root2 is iirational​

Answer 1

Answer:

let it be rational then we can write them in the form of p/q where p and q are integers...

then 4√2=p/q

√2 = p/4q

although p and q are integers then p/4q is rational and if √2 equal that it should also be rational but this contradict the fact that √2 is irrational...

hence our contradiction was wrong...hence 4√2 is proved to be irrational...

hope this helps you.... mark as brainliest

Answer 2

Answer:

Hello

Step-by-step explanation:

Let us assume, to contrary that

$4 + \sqrt{2}$

is a rational number.

$4 + \sqrt{2} = \frac{p}{q} \: q =/ 0 \: and \: p, \: q$

$\sqrt{2} = \frac{p}{q} - 4 \\ \sqrt{2} = \frac{p - 4q}{q} \\ \sqrt{2} = a \: rational \: number$

But this contradicts the fact that

$\sqrt{2} is \: irrational$

okk