Question

provide a detailed solution. ( i stand for iota(class 11th) its not a variable)

If you spam, you get a report and you lose your 100 points)

Answer 1

Answer:

$taking \: {i}^{4k} common \\ {i}^{4k} (1 + i + {i}^{2} + {i}^{3} ) = 0$

Step-by-step explanation:

${i}^{2} = - 1 \: \: and \: \: \: {i}^{3} = - i$