Provide explanation, will mark as brainliest if you solve it correct.
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I can try.
x,y,z are in GP
so y^2=xz....take log of this eqn .2logy=logx+logz......1
also x^p=y^q=z^¤
taking log of the above eqn:
(1/p)logx=(1/q)logy=(1/¤)logz......2
substitute the value of log x from eqn 1 in eqn 2.
(1/p)logx=(1/q)(logx+logz)/2+(1/¤)logz
x,y,z are in GP
so y^2=xz....take log of this eqn .2logy=logx+logz......1
also x^p=y^q=z^¤
taking log of the above eqn:
(1/p)logx=(1/q)logy=(1/¤)logz......2
substitute the value of log x from eqn 1 in eqn 2.
(1/p)logx=(1/q)(logx+logz)/2+(1/¤)logz
Shreyas6788:
its y²=xz nice try but its not working.
sorry mate.
I wasnt able to solve it.
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