Math, asked by ighhjgd, 10 months ago

provide me answer of this question

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Answered by master55538

0

Answer:

sin(90-theta)*sin theta-1/tan theta=

=cosA*sinA*cosA/sinA-1

=cos^2A-1

=-sin^2A

where A= theta

ok hence proved...........

(sin^2 theta+ cos^2 theta=1)

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