Provide that √7 is irrational number.
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Here is u r answer
Step-by-step explanation:
Let us assume that √7 be rational.
And we know that ever rational no can be written as the form of p/q where q≠ 0
√7 = p / q
√7 x q = p
squaring on both sides
7q² = p² ------1.
p is divisible by 7
p = 7c [c is a positive integer] [squaring on both sides ]
p²= 49c²
subsitute p² in eqn(1) we get
7q² = 49 c²
q² = 7c²
q is divisble by 7
So we can say that q and p have a common factor 7 but this contradicts the fact thatp & q are co prime
This contradiction has been arised due to our wrong assumption that √7 is rational
So we conclude that √7 is irrational
Hence proved
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