Question

provided that the earth attracts a man of mass 60kg with force 540N initially at rest.calculate the velocity of man after 1 second falling towards earth.​

Answer 1

Answer:

Explanation:

given in question,

F = 540 N

mass = 60 kg

so, accletation of the body = force / mass

=> a = 540/60

=> a = 9 m/s^2

sice at the body is initiaally at rest, we can use the formula

v = u + at

here, u = 0 as body starts from rest

=> v = at

=> v = (9 x 1) m/s

=> v = 9 m/s

Answer 2

Answer:

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Explanation:

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