Question

provides good answer to the question✔​

Answer 1

Correct Question:-

• Haemoglobin contains 0.25% iron/weight the molecular mass of hemoglobin is 89600 calculate the no. of Iron (Fe) atoms present per molecule of hemoglobin$?$

Required Answer:-

• Molecular mass of Haemoglobin = 89600

• Percentage of Iron = 0.25% / weight. This means the total mass of Iron out of the total molecular mass of Haemoglobin is 0.25% of 89600.

GiveN mass of Iron:

• = 0.25% × 89600
• = 25/10000 × 89600
• = 1/400 × 89600
• = 224 gm of Iron.

Moles of Iron:

• = Given Mass / Atomic mass
• = 224 gm / 56 gm
• = 4 moles.

• Now here, 1 mole of Haemoglobin contains 4 moles of Iron (Fe). Then 1 molecule of Haemoglobin will have 4 atoms of Fe.

Hence:-

• No. of Iron atoms present per molecule of hemoglobin = 4

Answer 2

Answer:

Each subunit has a molecular weight of about 16,000 daltons, for a total molecular weight of the tetramer of about 64,000 daltons (64,458 g/mol). Thus, 1 g/dL = 0.1551 mmol/L. Hemoglobin A is the most intensively studied of the hemoglobin molecules.