Question

provie answer for this question with steps....thanks the correct answer is (7/5)R

Answer 1

In pic.1

Resistance 3 and 4 are in series so eq resistance of these two resistance is

R + R = 2R

Similarly for 6 and 7 resistance equivalent resistance is 2R.

In pic 2

All resistance are connected in parallel so

$\frac{1}{r \: eq} = \frac{1}{r} + \frac{1}{r} + \frac{1}{2r} + \frac{1}{r} + \frac{1}{2r} \\ \frac{1}{r \: eq} = \frac{2 + 2 + 1 + 2 + 1}{2r} \\ \frac{1}{r \: eq} = \frac{8}{2r} \\ \frac{1}{r \: eq} = \frac{4}{r} \\ r \: eq = \frac{r}{4}$

Mine answer is coming r/4

can't match to the option