Question

proving irrationality of number by using method of contradiction prove that 2-7√3 is a irrational number​

Answer 1

Step-by-step explanation:

let us assume 2-7√3 is a rational no. nd we know that rational no is a co prime nd in form of p/q where q not = 0

therefore,

2-7√3=p/q

2-p/q=7√3

2-p/q/7=√3

therefore,

√3 is a rational no. but it contradicts the fact that √3 is an irrational no. therefore our assumptions is wrong, therefore,

2-7√3 is an irrational no.