Question

Provo that both Triangles are congruent

Answer 1

In triangle ABE& ACE,


1)<AEB=<AEC (R)

2) AB=AC (H)

3)AE=AE(S)

BOTH ARE CONSIDERED CONGRUENT BY RHS FACT.


HOPE IT HELPS YA

Answer 2

As AE is perpendicular to BC

So we have,Δ ABE & Δ ACE

Therefore, in Δ ABE & Δ ACE

= > AB = AC ( same side of triangles)
=> ang.AEB = ang.AEC (each equals 90°)
=>AE = AE (common)

Hence, Δ ABE ≈ Δ ACE