Question

∆PRS is an exterior angel of ∆PQR.
so from the theorem of remote interior angel .
∆PQR=∆PQR+∆PQR
=40°+30°
=70°
In ∆RTS
∆TRS+∆RTS+∆TSR=.............sum of all angel of a triangle
.: ........+∆RTS+..........=180°
.:∆RST+90°=180°
.:∆RTS=...........​

Answer 1

Answer:

Answer :-Angle RTS = 90°

Answer 2

Step-by-step explanation:

i hope my answer will help you