∠PRS is exterior angle of ∆PQR ∠P=30°∠PRS=100° Find ∠Q. *
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Answer:
Given, Bisectors of ∠PQRand ∠PRS meet at point T.
To prove: ∠QTR=
2
1
∠QPR.
Proof,
∠TRS=∠TQR+∠QTR (Exterior angle of a triangle equals to the sum of the two interior angles.)
⇒∠QTR=∠TRS−∠TQR --- (i)
Also ∠SRP=∠QPR+∠PQR
2∠TRS=∠QPR+2∠TQR
∠QPR=2∠TRS−2∠TQR
⇒
2
∠QPR=∠TRS−∠TQR --- (ii)
Equating (i) and (ii),
∴∠QTR=
2
1
∠Q=65
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