prve √11 is a irrational no.
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let√11 be rational.
then it must in the form of a / b [b is not equal to 0] [a and b are co-prime]
√11 = a / b
=> √11 x b = a
squaring on both sides
=> 11b^2 = a^2 ------> (1)
a^2 is divisible by 11
a is divisible by 11
a = 11c [c is a positive integer] [squaring on both sides ]
a^2 = 121 c^2 --------- > (2)
substitute a^2 in equ (1) we get
11b^2 = 121c^2
b^2 = 11c^2
=> b is divisible by 11
thus a and b have a common factor 11
there is a contradiction
as our assumption a & b are co prime but it has a common factor.
so √11 is an irrational.
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