PS=3 SQ=6 QR=5 PT=x & TR=y .Give any two pairs of values of x&y such that line ST parallel QR
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Answer:
Step-by-step explanation:
PS/SQ=3/5
or SQ/PS=5/3
SQ/PS+1=5/3 +1
SQ+PS/PS=5+3/3
PQ/PS=8/3
If
ST||QR
Then
∆PQR≈∆PST
So,
PQ/PS=PR/PT
8/3=28/PT
PT=28*3/8=10.5...
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