Question

PS=3 SQ=6 QR=5 PT=x & TR=y .Give any two pairs of values of x&y such that line ST parallel QR​

Answer 1

Answer:

Step-by-step explanation:

PS/SQ=3/5

or SQ/PS=5/3

SQ/PS+1=5/3 +1

SQ+PS/PS=5+3/3

PQ/PS=8/3

If

ST||QR

Then

∆PQR≈∆PST

So,

PQ/PS=PR/PT

8/3=28/PT

PT=28*3/8=10.5...

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