PS=8 cm, PQ= 3 cm, PX = 5 cm.
Name all edges of having length 3 cm ?
Answers
Answer:
Steps of Construction :
1. With P and Q as centers, draw arcs on both sides of PQ with equal radii. The radius should be more than half the length of PQ.
2. Let these arcs cut each other at points R and RS
3. Join RS which cuts PQ at D. Then RS=PQ. Also ∠POR=90∘.
Hence, the line segment RS is the perpendicular bisector of PQ as it bisects PQ at P and is also perpendicular to PQ. On measuring the lengths of PR=4cm, QR=4 cm Since PR=QR, both are 4cm each
∴PR=QR.
Step-by-step explanation:
1) Compounded Annually :
P=Rs.80000
R=10% p.a.
T=121 years ⟹n=1+21
Amount for 1st year.
A=P[1+100R]n
=Rs.80000[1+10010]=Rs.88000
SI on Rs. 88000 for next 1/2 year
=Rs.88000×10010×21=Rs.4400
Therefore, Amount = Rs.88000+Rs.4400 = 92400Rs.
2) Compounded half yearly :
P=Rs.80000
R=10% p.a.=5% per half year
T=121 years ⟹n=3
A=Rs.80000[1+1005]3
A=Rs.92610
Thus, the difference between the two amounts = Rs.92610−Rs.92400 =Rs.210