Question

PS is a median of trianglePQR. Prove that PQ+QR+ PR>2PS.​

Answer 1

Answer:

Here is your answer

In ∆ PQR

1. PQ + QS > PS

【 The sum of any two sides of triangle is greater than the third side】

2. PR + RS > PS

【 The sum of any two sides of triangle is greater than the third side】

3. Therefore adding 1 and 2

PQ+ QS+ PR+ RS >2PS

PQ+ QR+ PR> 2PS

【 as QR = QS + RS】

HENCE PROVED .