PS is an altitude of an isosceles triangle PQR in which PQ =PR . Show that PS bisects angle P .
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bro suvasuvi , Sorry to say this , but your answer is incorrect , to prove by using SAS , u need the angle to be included between the two sides u used for proving , which u havent
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Step-by-step explanation:
in triangle PQR
PR=PQ
in triangles PQS and PRS
PQ=PS ( proved above )
PS=PS (common)
anglePSQ = anglePSR ( 90degree each )
by RHS, trianglePQS is congruent to trianglePRS
so by CPCT , angleQPS = angleRPS ...
or in other ways , PS bisects angleP
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