Question

PS is the bisector of angle QPR. Prove that (i) angle QPS + angle PSR = angle PRT (ii) angle PQS + angle PRT = 2 × angle PSR
Please answer it ASAP
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Answer 1

Answer:

explained in the attachment..just use exterior angle theorem

Answer 2

Answer:

∆PRT=∆PSR

∆QPS=∆SPR

∆PRT=∆PSR+∆QPS

∆QPS=∆SPR

∆PRT=∆PSR+∆QPS hence proved

∆QPS+∆PQS=∆PSR

∆PQS=∆PSR-∆QPS from 1st equation

∆PSR+∆SPR=∆PRT hence proved

add 1st and 2nd equation

∆PQS+∆PRT=∆PSR-∆QPS+∆SPR+∆PSR

∆PQS+∆PRT =2(∆PSR)

Step-by-step explanation:

this is the correct answer mark as brainlist