PS
PT
5. In given A PQR, if ST// QR Then
SQ
TR
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PQR is a triangle. ST is parallel to QR
By basic proportionality theorem in ΔPQR
PSPQ=PTPR
By componendo and dividendo
PSPQ=PTPR⇒PQ−PSPQ+PS=PR−PTPR+PT
SQPQ+PS=TRPR+PT
RT(PQ+PS)=SQ(PR+PT)
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