PSE ~ TSV. In PSE, PS = 4.4 cm, SE = 5.1 cm, PE = 5.5 cm and
PS 5
Construct PSE and TSV.
Answers
Answer:
Given : ΔPSE ≈ Δ TSV
PS= 4.4cm, SE= 5.1cm, PE = 5.5cm
PS/TS = 5/3
To Find : Construct ΔPSE and Δ TSV
Solution:
ΔPSE ≈ Δ TSV
PS/TS = PE/TV = SE / SV = 5/3
Construct ΔPSE
Step 1: Draw a line segment PS = 4.4 cm
Step 2 : Using compass width = 5.1 cm and taking S as center Draw an arc
Step 3 : Using compass width = 5.5 cm and taking P as center Draw an arc such that it intersects arc drawn in previous step at E
Step 4 : Join PE & SE
ΔPSE is constructed
Construct ΔTSV
Draw an acute angle at S on PS
Take point at equal distance on by one
Join 5th point with P
Draw a line parallel to that passing through 3rd point and intersecting PS at T
Draw a line parallel to PE passing through T and intersecting SE at V
ΔTSV is constructed
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