Question

pseudocode to check whether a number is a palindrome​

Answer 1

n=int(input("Enter number:"))

temp=n

rev=0

while(n>0):

   dig=n%10

   rev=rev*10+dig

   n=n//10

if(temp==rev):

   print("The number is a palindrome!")

else:

   print("The number isn't a palindrome!")

Program Explanation :

1. User must first enter the value of the integer and store it in a variable.
2. The value of the integer is then stored in another temporary variable.
3. The while loop is used and the last digit of the number is obtained by using the modulus operator.
4. The last digit is then stored at the one’s place, second last at the ten’s place and so on.
5. The last digit is then removed by truly dividing the number with 10.
6. This loop terminates when the value of the number is 0.
7. The reverse of the number is then compared with the integer value stored in the temporary variable.
8. If both are equal, the number is a palindrome.
9. If both aren’t equal, the number isn’t a palindrome.
10. The final result is then printed.

Hope it helps :)

Answer 2

Answer:

❤ANSWER ❤

• Declare two variables: one stores the given number, and the other stores the reversed number.
• Run the do-while loop until the number of digits in the reversed number are equal to the number of digits in the given number. ...
• Check if the reversed number is equal to the given number.

Explanation:

It's Pandit Manish.... xd....