Question

pseudocode to design a simple calculator​

Answer 1

Answer:

logically, you can use what you come up with to create quality software, using real programming languages.

Step 1

Think about what it takes to make a calculator work at a high level and write down those high-tasks on a sheet of paper. They might appear as shown below:

inputData = Read_Input() result = Perform_Calculations(inputData) Display_Results(result)

These are the actions that occur when you type numbers into a calculator, press a function key and view the results. The first statement calls a method that reads input from a user. That method returns results which go into the Input_Data variable. The next statement passes that data to a function named Perform_Calculations. Perform_Calculations calculates a result and returns it to this code which stores it in the result variable. The final statement passes that result to a function that displays it.

Step 2

Draw a large box around those statements. This box represents the program's main module. Draw another large box on the paper and write "Read_Input()" at the top of it. This box represents the function that reads the input needed to perform calculations. Type statements into the box that you think need to occur to retrieve information from a user. Those statements might look like the ones shown below:

Print "Enter First Number" firstNumber = Read_Input Print "Enter Second Number" secondNumber = Read_Input Print "Enter an Operator" Print "Enter an Operator" operator = Read_Input Return firstNumber, secondNumber, operator

The firstNumber, secondNumber and operator variables will contain the values a user enters via some method. The final statement returns the variables to the calling module.

Step 3

Draw a second box on the paper and write "Perform_Calculations(firstNumber, secondNumber, operator) at the top of it. Add statements to this box needed to perform calculations using the two numbers and operator passed to the function. Those statements might look similar to the following statements:

if operator = "+" result = firstNumber + secondNumber

else if operator = "-" result = firstNumber - secondNumber

else if operator = "*" result = firstNumber * secondNumber

else if operator = "/" result = firstNumber / secondNumber

return result

This code uses an if statement to determine the statement to execute based on the operator's value. After one of the statements computes the result, the last statement passes the result back to the calling module.

Step 4

Draw a final box on the paper and write "Display_Result(result)" at the top of the box. Write down the statements needed to present the result to a user, such as this:

Print result

Review the pseudocode and follow the logic beginning at the first statement in the main module. Look for logical flaws in the code as you step through it. Identify those if they exist, and correct your pseudocode if necessary.

Explanation:

hope it's helps you ✌️

Answer 2

Answer:

The C program code for calculator is shown here.

Explanation:

#include <stdio.h>

int main(){

  char Operator;

  float num1, num2, result = 0;

  printf("\n Enter any one operator like +, -, *, / : ");

  scanf("%c", &Operator);

  printf("Enter the values of Operands num1 and num2 \n : ");

  scanf("%f%f", &num1, &num2);

  switch(Operator){

//Addition

     case '+': result = num1 + num2;

        break;

//Subtraction

     case '-': result = num1 - num2;

        break;

//Multiplication

     case '*': result = num1 * num2;

        break;

//Division

     case '/': result = num1 / num2;

        break;

//Invalid Input

     default: printf("\n Invalid Operator ");

  }

//Answer

  printf("The value = %f", result);

  return 0;

}

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