Question

PT BISECTS ANGLE RPS AND ANGLE Q=ANGLE R.
PROVE THAT PT IS PARALLEL QR.

THE ONE WHO WILL ANSWER FIRST WILL BE MARKED AS BRAINLIEST
PLEASE ANSWER FAST

Answer 1

Answer:

IN TRIANGLE PQR,

ANGLE Q = ANGLE R

ANGLE RPS = ANGLE Q+ANGLE R (EXTERIOR ANGLE PROPERTY) ------ (1)

ANGLE RPS = ANGLE SPT + ANGLE TPR

​

ANGLE SPT = 1/2 ANGLE RPS (SINCE PT BISECTS ANGLE RPS)

​ANGLE SPT = 1/2 (ANGLE Q + ANGLE R) (FROM (1))

ANGLE SPT  = ANGLE Q (SINCE ANGLE Q = ANGLE R)

THESE ANGLES FORM A PAIR OF CORRESPONDING ANGLES ONLY WHEN PT IS PARALLEL TO QR.

HENCE PROVED.

PLS MARK ME AS BRAINLIEST

Answer 2

Answer:

Step-by-step explanation:

TRIANGLE PQR,

ANGLE Q = ANGLE R

ANGLE RPS = ANGLE Q+ANGLE R (EXTERIOR ANGLE PROPERTY) ------ (1)

ANGLE RPS = ANGLE SPT + ANGLE TPR

​

ANGLE SPT = 1/2 ANGLE RPS (SINCE PT BISECTS ANGLE RPS)

​ANGLE SPT = 1/2 (ANGLE Q + ANGLE R) (FROM (1))

ANGLE SPT  = ANGLE Q (SINCE ANGLE Q = ANGLE R)

THESE ANGLES FORM A PAIR OF CORRESPONDING ANGLES ONLY WHEN PT IS PARALLEL TO QR.

HENCE PROVED.

PLS MARK ME AS BRAINLIEST

Read mhttps://brainly.in/question/11