PT cotA-cot2A=cosec8
dnavneetk9549:
it should be cosec2a
not cosec 8
i am getting the answer as cosec 2a
please check out my answer
yes it is correct answer
Hmm
Answers
Answered by
8
hi mate here is ur answer
cot a - cot 2a
cosa / sina - cos2a/sin2a
cosa.sinn2a- sina.cos2a/(sina.sin2a) [taking lcm ]
use the property sinxcosx-sinycosx = [sin(x-y)]
we get ,
sin(2a-a)/sina . sin2a
= sina/sina .sin2a [ as sin a and sina.sin2a is divided cancel sin a]
we get, 1/sin2a = cosec2a
hope it helps!!!
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