Question

Pt is a tangent and pab is a secantto the circle with centre o

Answer 1

At a point of a circle there is one and only one tangent.

The tangent at any point of a circle is perpendicular to the radius through the point of contact.

The lengths of tangents drawn from an external point to a circle are equal.

Centre of the circle lies on the bisector of the angle between the two tangents.

Theorem 1:- If two chords of a circle intersect inside or outside the circle, then the rectangle formed by the two parts of one chord is equal in area to the rectangle formed by the two parts of the other.

Given:- Two chords AB and CD of a circle such that they intersect each other at a point P lying inside in figure (i) or outside in figure (ii) of the circle.

To prove: - PA.PB = PC.PD

Construction:-AC and BD are joine P.

Proof:-

Case - (1) in figure (i) P lies inside the circle

In  we have[Angles in jthe same segment][vertically opposite angles](AA similarity)

Case- (2) In figure (ii) P lies outside the circle

(limear pair)and  (opposite angles of acyclicq and)In [Proved above][Common](AA similarity)Hence, in either case,Or, PA.PB = PC.PD

Theorem 2. If PAB is a secant to a circle intersecting it at A and B and PT is a tangent then PA.PB = PT2.

Given: - PAB is secant intersecting the circle with centre O at A and B and a tangent PT at T.

To Prove: - PA.PB = PT2

Construction: - is drawn OA, OP and OT are joined.

Proof: -     PA = PM – AM

                   PB = PM + MB

                           

Also PM2 = OP2 - OM2 [Pythagoras theo.]