Question

PT is a tangent to a circle whose Centre is O if PT equal to 1.2 cm and PO is 3.7 cm and the radius of circle is​

Answer 1

Answer:

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Answer 2

Answer:

in triangle OPT

by pythagoras theorem

(3.7)^2 =(1.2)^2+ (OT)^2

13.69=1.44+(OT)^2

13.69-1.44=OT^2

12.25=OT^2

OT=radius of square =3.5cm