Question

[Pt(NH3)(H2O)(SCN)(N2O)]3 how many isomers of this compound ??
please answer it fast and correctly...

10
11
12
3​

Answer 1

There is a slight mistake in the question .The correct compound should be ${[Pt(NH_3)(H_2O)(SCN)(NO_2)]}^{3+}$

Given

A co-ordination compound ${[Pt(NH_3)(H_2O)(SCN)(NO_2)]}^{3+}$

To Find

Number of isomer.

Concept

SCN and $N_2O$ are ambidentate ligend .They can bind with central metal ion with different sites.

${SCN}^-$

The two sites are through -SCN (Known as thiocyanato) and through -NCS (Known as isothiocyanato).

${NO_2}^-$

The two sites are through -N(known as nitrito-N) and through -O(Nitrito-O)

Hence, there can be two isomer possible for each .

Now, For a square planar complex ion M(abcd), there exists three stereomer (geometrical isomer) :- 2 Cis and 1 trans.

Solutions

Solution involve slight use of permutation and combination.

Follow these steps :-

• First consider three steroisomers named A,B,C.

• Now for isomer A, there are total four types of ligend combination using ${SCN}^-\:and\:{NO_2}^-$ are possible. These are ${[Pt(NH_3)(H_2O)(SCN)(NO_2)]}^{3+}\:\\\:{[Pt(NH_3)(H_2O)(NCS)(NO_2)]}^{3+}\:\\\:\:{[Pt(NH_3)(H_2O)(NCS)(ONO)]}^{3+}\:\\ \:\:{[Pt(NH_3)(H_2O)(SCN)(ONO)]}^{3+}\:$

• Thus, there are four possible isomers of each of A,B and C.

• Hence,the compound has all total 12 isomers.

Details of isomerism

• There are four ligend isomers.

• For each ligend isomers, there exists three geometrical isomers.

Note :- Ligend is not the correct spelling.It is a technical glitch.The correct spelling has a in place of e.

Answer 2

Answer:

3 isomers are present in this compound