PT||QR and QT || RS. Show that ar ( PQR) = ar ( QTS )
vanshika2002:
plz canu give the figure
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Answered by
1
triangle PQR and TQR are on the same base (QR) and between the parallels
(PT ll QR)
Therefore,
ar(PQR)=ar(TQR) ..... (1)
In the same way, triangle QTS and TQR are on the same base QT and between the parallels QT and RS.
So,
ar(QTS)=ar(TQR) ..... (2)
From (1) and (2), we have,
ar(PQR)=ar(QTS)
Hence Proved.
(PT ll QR)
Therefore,
ar(PQR)=ar(TQR) ..... (1)
In the same way, triangle QTS and TQR are on the same base QT and between the parallels QT and RS.
So,
ar(QTS)=ar(TQR) ..... (2)
From (1) and (2), we have,
ar(PQR)=ar(QTS)
Hence Proved.
Attachments:
Answered by
1
Heya !!!
Given that: PT || QR and QT || RS
To Prove: ar(ΔPQR)=ar(ΔQTS)
Proof:
Since triangle PQR and TQR are on the same base QR and between the parallels PT and QR. Therefore,
ar(ΔPQR)=ar(ΔTQR) ..... (1)
Similarly, triangle QTS and TQR are on the same base QT and between the parallels QT and RS. So,
ar(ΔQTS)=ar(ΔTQR) ..... (2)
From (1) and (2), we have,
ar(ΔPQR)=ar(ΔQTS)
Hence Proved.
Diagram is given below:-
Hope it helps u :)
Given that: PT || QR and QT || RS
To Prove: ar(ΔPQR)=ar(ΔQTS)
Proof:
Since triangle PQR and TQR are on the same base QR and between the parallels PT and QR. Therefore,
ar(ΔPQR)=ar(ΔTQR) ..... (1)
Similarly, triangle QTS and TQR are on the same base QT and between the parallels QT and RS. So,
ar(ΔQTS)=ar(ΔTQR) ..... (2)
From (1) and (2), we have,
ar(ΔPQR)=ar(ΔQTS)
Hence Proved.
Diagram is given below:-
Hope it helps u :)
Attachments:
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