Math, asked by sitishaggarwal6660, 11 months ago

PT sin3x-sinx÷cosx-cos3x=cot2x

Answers

Answered by sandy1816

2

Step-by-step explanation:

sin3x-sinx/cosx-cos3x

=[2cos(3x+x/2)sin(3x-x/2)]/ [-2sin(x+3x/2)sin(x-3x/2)]

=[2cos2xsinx]/[-2sin2xsin(-x)]

=(2cos2x sinx)/(2sin2x sinx)

=cos2x/sin2x

=cot2x

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