PtCl4.2HCl precipitate zero moles of AgCl with excess AgNO3 .fromthis data, how we can calculate the secondary valency ?
similarly, CoCl34NH3 will give 1 mole of AgCl. How its secondary valency is calculated?
Answers
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Hey buddy,
● Answer-
PtCl4.2HCl Secondary valency = 6
CoCl34NH3 Secondary valency = 6
● Explanation-
- Secondary valency is nothing but co-ordination number of the complex
- In PtCl4.2HCl, zero moles of AgCl precipitated with AgNO3 which indicates all 6 Cl- ions are present inside the co-ordination sphere.
Structure- [PtCl4(HCl)2]
Thus coordination nunber 6.
Therefore, secondary valency is 6.
- In CoCl3.4NH3, 1 mole of AgCl precipitated with AgNO3 which indicates all 1 Cl- ions is present outside the co-ordination sphere.
Structure - [CoCl2(NH3)4]Cl
Thus coordination nunber 6.
Therefore, secondary valency is 6.
Hope this is helpful...
● Answer-
PtCl4.2HCl Secondary valency = 6
CoCl34NH3 Secondary valency = 6
● Explanation-
- Secondary valency is nothing but co-ordination number of the complex
- In PtCl4.2HCl, zero moles of AgCl precipitated with AgNO3 which indicates all 6 Cl- ions are present inside the co-ordination sphere.
Structure- [PtCl4(HCl)2]
Thus coordination nunber 6.
Therefore, secondary valency is 6.
- In CoCl3.4NH3, 1 mole of AgCl precipitated with AgNO3 which indicates all 1 Cl- ions is present outside the co-ordination sphere.
Structure - [CoCl2(NH3)4]Cl
Thus coordination nunber 6.
Therefore, secondary valency is 6.
Hope this is helpful...
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