Math, asked by saurabhkumar14419, 1 year ago

Pulkit is 12 year older than aarav 4 year ago Pulkit was 7 times as old as Aarav find their present age

Answers

Answered by Darvince
17

Answer:

The Present Ages are -

  • Aarav = 6 years old
  • Pulkit = 18 years old

Step-by-step explanation:

Gívєn -

Pulkit = is 12 year older than Aarav

4 year ago = Pulkit was 7 times as old as Aarav

Tσ fínd -

Their present ages

Sσlutíσn -

Let the present Ages be -

  • Aarav as x
  • Pulkit as (x + 12)

\rule{300}{1.5}

Ages Before 4 years -

  • Aarav = (x - 4)
  • Pulkit = (x + 12) - 4

\rule{300}{1.5}

According to the Question -

4 year ago = Pulkit was 7 times as old as Aarav

➡ (x + 12) - 4 = 7(x - 4)

➡ x + 12 - 4 = 7x - 28

➡ x + 8 = 7x - 28

➡ x - 7x = - 28 - 8

➡ - 6x = - 36

➡ x = 36/6

➡ x = 6

Aarav is presently 6 years old

\rule{300}{1.5}

Pulkit's present age =

➡ (x + 12)

➡ 6 + 12

➡ 18

Pulkit is presently 18 years old.

\therefore The Present Ages are -

  • Aarav = 6 years old
  • Pulkit = 18 years old
Answered by kajal1712
16

❤❤❤❤❤

\huge\underline\mathfrak\red {Hello}\\

Let present age of-

  • Aarav = x years old
  • Pulkit = x+12 years old

-------------------------------

4 years ago, the age of-

  • Aarav = x-4 years old
  • Pulkit = x+12-4 years old

--------------------------------

According to question,

x+12-4 = 7(x-4)

x+8 = 7x-28

7x-x = 28

6x = 36

x = 36/6

x = 6 years

--------------------------------

So Pulkit present age -

x + 12

6 + 12

18 years

--------------------------------

Answer- Aarav is 6 years old whereas Pulkit is 18 years old ☺✌

\boxed{Plz \:Mark\: my\: answer\: as \: brainliest...}

❤❤❤❤❤

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