Question

pulkits is 12 year old than Aarav. 4 years ago pulkit was 7 times older than Aarav. find their present age.​

Answer 1

Answer:

Aarav= 6 years old

Pulkit= 18 years old

Step-by-step explanation:

Let Aarav's age be $x$.

⇒ Pulkit's age = $x+12$

Now, 4 years ago their ages will be,

Aarav = $x-4$

Pulkit = $x+12-4$ = $x+8$

As Pulkit was 7 times older than Aarav,

$7(x-4)=x+8$

⇒$7x-28=x+8$

⇒$7x-x=8+28$

⇒$6x=36$

⇒$x=\frac{36}{6} =6$

∴ Aarav's age = $x$ = $6$

  Pulkit's age = $x+12$ = $6+12$ = $18$

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Answer 2

Answer:

let the age of pulkits=x

age of aarvav=y

A.T.Q

x=y+12

x-y=12..............(1.)

4 years aGo

the age of pulKit=(x-4)years

the age of arav=(y-4)years

again A.T.Q

x-4=7(y-4)

x-4=7y-28

x-7y=-28+4

x-7y=-24........................(2.)

from Ist and IInd equation

(see in attachment)

so,the age of pulkit is 18 years

the age of arav is 6 years