Physics, asked by akhitech2002, 4 months ago

pulse of light of duration 10−6 s is absorbed completely by a small object initially at rest. If the power of the pulse is 60 × 10−3 W, calculate the final momentum of the object.

Answers

Answered by ankan2778
0

Answer:

Duration of the absorption of light pulse, t = 10 ^ - 6 * s

Power of the pulse P = 60 * 10 ^ - 3 W

Final momentum of the object, P = U/C

Velocity of light, C = 3 * 10 ^ 8

Energy U = pow x time

Momentum,

P = (60 * 10 ^ - 3 * 10 ^ - 6)/(3 * 10 ^ 8)

P=20*10^ -17 kg m s^ -1

Similar questions