Question

pulse was created in a stretched string of length 5m is observed that pulse return after reflection at a point of five times in 10 seconds calculate the speed

Answer 1

Given:- distance-5m

It was observed 5 times in 10 seconds =10÷5=2sec.

Now ,

By using

2d=v×t

v=2d÷t

=2×5÷2=10÷5

=5m/s

Therefore, speed =5m/s