Pump M is filling an empty water tank at a constant rate. At this rate, it can fill 120
gallons in 30 minutes. Working at a constant rate, Pump J takes 10 fewer minutes than
Pump M to fill 120 gallons.
Write the equation shows the amount of water, , in gallons, Pump J can fill in n
minutes.
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Solution :-
Let us assume that, the amount of water in gallons, Pump J can fill per minutes is equal to x .
So,
→ Total water filled = 120 gallons
→ Time taken = 10 minutes fewer than pump M = 30 - 10 = 20 minutes .
then,
→ x * 20 = 120
→ x = 6 gallons .
therefore,
→ The amount of water filled in n minutes = 6 * n = 6n gallons . (Ans.)
hence, required equation is equal to 6n .
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