Math, asked by himanshuc266, 1 month ago

Pump M is filling an empty water tank at a constant rate. At this rate, it can fill 120
gallons in 30 minutes. Working at a constant rate, Pump J takes 10 fewer minutes than
Pump M to fill 120 gallons.
Write the equation shows the amount of water, , in gallons, Pump J can fill in n
minutes.

Answers

Answered by RvChaudharY50
1

Solution :-

Let us assume that, the amount of water in gallons, Pump J can fill per minutes is equal to x .

So,

→ Total water filled = 120 gallons

→ Time taken = 10 minutes fewer than pump M = 30 - 10 = 20 minutes .

then,

→ x * 20 = 120

→ x = 6 gallons .

therefore,

→ The amount of water filled in n minutes = 6 * n = 6n gallons . (Ans.)

hence, required equation is equal to 6n .

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