Puneet has a recurring deposit account in a bank and deposits 400 per
month. If he receives 10100 at the time of maturity, find the time for which
the account is held if the rate of interest is 5% p.
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Given Puneet has a recurring deposit account in a bank and deposits 400 per month. If he receives 10100 at the time of maturity, find the time for which the account is held if the rate of interest is 5% p.
- So Deposit per month P = 400
- Rate of interest r = 5%
- Time = n
- So A = P x n + P x n(n + 1) / 2 x 12 x r/100
- = 400 x n + 400 x n(n + 1) / 24 x 5/100
- = 400 n + 5n (n + 1) / 6
- 10100 = 2400n + 5n^2 + 5n / 6
- 60600 = 2405 n + 5n^2
- 5n^2 + 2405 n – 60600 = 0
- n^2 + 481 n – 12120 = 0
- Using x = - b + - √b^2 – 4ac / 2a we have
- n = -481 +- √(481)^2 – 4 (1) (-12120) / 2(1)
- = - 481 + - √231361 + 48480 / 2
- = - 481 + - 529 / 2
- = 48 / 2
- n = 24
- So the number of months will be 24 months = 2 years.
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