Puneet purchased 36 bananas for rs 150. Six of them were rotten which he threw. He sold three-fifth of the remaining bananas at a profit of 15% and rest at a loss of 3%. Find his profit or loss in percentage
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if he purchased 36 bananas and 6 of them were rotten the he has,
36-6=30 bananas.
A/Q : bananas sold=30×3/5=18 bananas.
36-6=30 bananas.
A/Q : bananas sold=30×3/5=18 bananas.
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36-6=30
30 =3:5= 18:30 (3/5th part of total banana = 18 bananas)
18 bananas at 15% profit : 4.16×18= 75+15% = 75+11.25= 86.25
(1 banana cost price : 150÷36 = 4.16 )
loss at 3% = 4.16× 12 = 49.92 - 3% loss
=49.92-1.92 = 48
total earning = 86.25+ 48= 134.25
so he us in loss
total cp =150
total sp = 134.25
loss= 15.75
equal to approxx 10 % loss
any doubt?
30 =3:5= 18:30 (3/5th part of total banana = 18 bananas)
18 bananas at 15% profit : 4.16×18= 75+15% = 75+11.25= 86.25
(1 banana cost price : 150÷36 = 4.16 )
loss at 3% = 4.16× 12 = 49.92 - 3% loss
=49.92-1.92 = 48
total earning = 86.25+ 48= 134.25
so he us in loss
total cp =150
total sp = 134.25
loss= 15.75
equal to approxx 10 % loss
any doubt?
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