Chemistry, asked by manishmakwana576, 8 months ago

Pure hexane has a vapor pressure of 0.186 atm at room temperature. Calculate the vapor pressure of the hexane 0.135 moles of I2 is mixed with 9.62 moles of hexane

Answers

Answered by vidhishagawand2002
0

Answer:

Explanation:

mole fraction of hexane = 9.62/ 9.62+0.135

= 0.98

vapor pressure of the hexane = mole fraction of hexane *vapor pressure of

pure hexane

= 0.186* 0.98

= 0.1822 atm

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