Pure hexane has a vapor pressure of 0.186 atm at room temperature. Calculate the vapor pressure of the hexane 0.135 moles of I2 is mixed with 9.62 moles of hexane
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Answer:
Explanation:
mole fraction of hexane = 9.62/ 9.62+0.135
= 0.98
vapor pressure of the hexane = mole fraction of hexane *vapor pressure of
pure hexane
= 0.186* 0.98
= 0.1822 atm
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