Question

pure inductor of inductance
0.1H is connected
to an AC
Source (of rms voltage) 220v
angular frequency of 300Hz.
The rms current is?​

Answer 1

Given:

Pure inductor of inductance 0.1H is connected

to an AC Source (of rms voltage) 220 V and angular frequency of 300Hz.

To find:

RMS value of current .

Calculation:

Let inductive reactance be

$\therefore \: X_{L} = \omega \times L$

$= > \: X_{L} = 300 \times 0.1$

$= > \: X_{L} = 30 \: ohm$

RMS value of current can be calculated by the ratio of of RMS voltage and inductive reactance.

$\therefore \: I_{rms} = \dfrac{V}{ X_{L}}$

$= > \: I_{rms} = \dfrac{220}{ 30}$

$= > \: I_{rms} = 7.33 \: amp$

So , final answer is:

$\boxed{ \rm{ I_{rms} = 7.33 \: amp}}$