Question

Pure oxygen is prepared by thermal decomposition of KClO3 according to the equation: Calculate the volume of oxygen gas liberated at STP by heating 12.25g KClO3(g) [Atomic mass of K=39, Cl =35.5 and O =16]

Answer 1

The chemical equation for decomposition of KClO

3

can be written as:

2KClO

3

→2KCl+3O

2

245 g of KClO

3

gives 67.2 L of O

2

at STP.

12.25 g of KClO

3

gives

245

67.2

×12.25 =3.36 L.

Hence, option D is correct.

Answer 2

Answer:

The chemical equation for decomposition of KClO

3

can be written as:

2KClO

3

→2KCl+3O

2

245 g of KClO

3

gives 67.2 L of O

2

at STP.

12.25 g of KClO

3

gives

245

67.2

×12.25 =3.36 L.

Hence, option D is correct.

Explanation:

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