Question

pure rotational spectrum of diatomic molecule, the spacing distance is equal to ?​

Answer 1

Answer:

For a rigid rotor diatomic molecule, the selection rules for rotational transitions are ΔJ = +/-1, ΔMJ = 0 . The rotational spectrum of a diatomic molecule consists of a series of equally spaced absorption lines, typically in the microwave region of the electromagnetic spectrum.

Answer 2

In the pure rotational spectrum of a diatomic molecule, the spacing distance is equal to 2B.

• For the pure rotational spectrum of a diatomic rigid molecule, the spacing between various energy levels is 2B.
• Here B is called rotational constant.
• The value of B is given as-
• $B=\dfrac{h}{8π^2Ic}$.
• Where h is the plank's constant.
• 'I' is the moment of inertia.
• Here 'c' is the speed of light.