Chemistry, asked by vaishnavi8858, 1 year ago

Pure water freezes at 273 K and 1 bar. The addition of 34.5 g of ethanol to 500 g of water
changes the freezing point of the solution. Use the freezing point depression constant of
water as 2 K kg mol-'. The figures shown below represent plots of vapour pressure (V.P.)
versus temperature (T). [Molecular weight of ethanol is 46 g mol” |
Among the following, the option representing change in the freezing point is (Single option
correct)
Water
Water
V.P/bar
Water+Ethano!
V.P/bar-
Water+Ethanol
271 273
T/K-
271 273
TIK-
Water
Water
V.P/bar
IN
V.P/bar-
Water+Ethanol
Water+Ethanol
270 273
T/K-
270 273
TIK​

Answers

Answered by ayan4312
0

PUBG LOVER DHEHEWJSJR4RRHHJG

Similar questions