Question

Purple coloured solution of potassium permanganate
becomes colourless when gas 'X' is passed through
it. Gas 'X' is​

Answer 1

Answer:

the name of the X is the bromine gas

Answer 2

Answer:

Sulfur dioxide

Explanation:

Potassium permanganate is a very strong oxidizing agent. When the purple solution of potassium permanganate is treated with sulfur dioxide gas, the solution become colorless. This is because the permanganate ion reduces to Manganese(II) which is almost colorless and sulfur dioxide gas is oxidized to form sulfate ions.

Hence, Gas X is Sulfur dioxide gas . ($SO_2$)