Question

push of 180 N and pull of 350 N act simultaneously at a point. Find the resultant of the
forces, if the angle between them be 135

Answer 1

(180²+ 350²+ 2×180×350×cos135°)½

Bcz

Say A and B are two forces and angle between them is 135 then resulting force will be

A²+B²+2A.B.cos135

Answer 2

Answer:

The resultant force between the push and the pull force is 256.55 N.

Explanation:

Given,

The force due to the push at a given point, A = 180 N

The force due to the pull at the same point, B = 350 N

The angle between the two forces = 135°

Let the resultant force = R

As we know,

• The resultant force can be calculated by the equation given below:
• $R = \sqrt{A^{2}+ B^{2} + 2ABcos\theta }$

Now, after putting all the values given in the equation, we get;

• $R = \sqrt{(180)^{2}+ (350)^{2} + 2\times A \times B \times cos135\textdegree }$

Here, cos 135° = -0.701

Therefore,

• $R = \sqrt{32400 + 122500 + (2\times 180 \times 350 \times -0.707) }$
• $R = \sqrt{154900 + (-89082) }$
• $R = \sqrt{65818 }$
• R = 256.55 N

Hence, the resultant force is 256.55 N.