Question

Put a = 2 and b =1 in the given polynomial. Hence the required Value of that Expression is 0
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Answer 1

Answer:

is not a polynomial.

Explanation:

In an algebraic expression, if the powers of the variables are whole numbers then the algebraic expression is a polynomial.

(i)

y+

1

y

=y+y-1

Here, one of the powers of y is −1, which is not a whole number. So, y +

1

y

is not a polynomial.

Answer 2

Answer:

Explanation:

Let us first divide the given polynomial x  

4

+x  

3

+8x  

2

+ax+b by (x  

2

+1) as shown in the above image:

From the division, we observe that the quotient is x  

2

+x+7 and the remainder is (a−1)x+(b−7).

Since it is given that x  

4

+x  

3

+8x  

2

+ax+b is exactly divisible by x  

2

+1, therefore, the remainder must be equal to 0 that is:

(a−1)x+(b−7)=0

⇒(a−1)x+(b

bye kyu ?