Question

put the value p(2) x²-5x+1​

Answer 1

$\begin{gathered}{\underline{\underline{\maltese{\Huge{\textsf{\textbf{\red{Solution: }}}}}}}}\end{gathered}$

$\implies\sf{p(2) = {x}^{2} - 5x + 1}$

$\implies\sf{p(2) = {2}^{2} - 5(2) + 1}$

$\implies\sf{p(2) = 4 - 10 + 1}$

$\implies\sf{p(2) = - 6 + 1}$

$\implies\sf{p(2) = \fbox\purple{ - 5}}$

Answer 2

$\huge\color{in}{\mid{\fbox{\tt{αɳѕωєя}}\mid}}$

⇥p(2) = x² - 5x + 1

⇥p(2) =2² - 5(2) + 1

⇥p(2) = 4 - 10 + 1

⇥p(2) = -6+1

⇛p(2) = -5

❥︎Mᥲɢıᥴᥲᥣ_Bᥣᥲᴢᥱ♡︎~