Question

Putting the I'd on deletion..



Rahul bought a car Rs. 4 lakhs in 2018. The rate of
depreciation is 10% per year. Find the depreciation
value of the car in the year 2020?

Solution P=4,00,000 R= 10%, N=_years.
A=P(_______) (Formula)
On substituting the values of P, N, and R solving we get
A=4,00,000 X _______ square
= 4000 X (_______)
= Rs.________
Depreciation in price = Cost price - A
= Rs.________​

Answer 1

Answer:

A = P ( 1 + R/100) N (Formula)

Explanation:

A = 400000 × (1 + 10/100)²

= 400000 × [(10+1)/10]²

= 400000 × 11/10 ×11/10

= 4000 × 121 = 484000

SO, the compound interest is = (484000 - 400000) = 84000

see this answer I am not sure