Question

Px=ax{2}+bx+c,c/a...?p(x)

Answer 1

★Answer :-

• According to question a polynomial is given and we have to find c/a

That's a theortical topic to discuss , Every polynomial has its zeroes and those zeroes satisfy the given equation.

$\sf\dfrac{-b}{a}=Sum\:of\:Zeroes$

$\sf\dfrac{c}{a}=Product\:of\:Zeroes$

So, here it has given c/a . So, it means that it is the product of zeros of this equation.

Answer 2

${ \huge{ \bold{\underline{ \underline{ \red{Question:-}}}}}}$

PX =ax {2}+bx+c,c/a....?p(x)

${ \huge{ \bold{\underline{ \underline{ \purple{Solution:-}}}}}}$

$\implies{\tt{\green{According \:, to \: the \: question\: a\: polynomial\: is \: given, \: here\: we\: have\: to \: c/a}}}$

$\implies{\tt{\blue{Sum \: of \: Zeros \: = \frac{-b}{a}}}}$

$\implies{\tt{\blue{product \: of \: Zeros \: = \frac{c}{a}}}}$

Here c/a is given ,so it shows that it is product of zeores of this equation.